(3-x)/-4 = (x+6)/3
subtract the terms on the right over to the left (everything)
[(3-x)/-4]-[(x+6)/3]=0
find a common denominator
for 4 and 3 which is 12
[-3(3-x)/12]-[4(x+6)/12]=0
multiply over
(-9+3x)/12 - (4x+24)/12= 0
[(-9+3x)-(4x+24)]/12 = 0 don't forget the negative
(-3+3x-4x-24)/ 12 = 0
combine like terms on the numerator then solve for x
(-3+3x-4x-24)= 0
(3-x)/-4=(x+6)/3
I have tried this one multiple times but i still can't get it.
2 answers
Typo after multiply over: Correction
is it's -9 not negative -3
[(-9+3x)-(4x+24)]/12 = 0 don't forget the negative
(-9+3x-4x-24)/ 12 = 0
combine like terms on the numerator then solve for x
(-9+3x-4x-24)= 0
is it's -9 not negative -3
[(-9+3x)-(4x+24)]/12 = 0 don't forget the negative
(-9+3x-4x-24)/ 12 = 0
combine like terms on the numerator then solve for x
(-9+3x-4x-24)= 0