3/((x+3)(x-3))- x/(x-3)(x-3) + 1/(x+3)
The LCD is (x-3)(x-3)(x+3)
= (3(x-3) - x(x+3) + 1/((x-3)(x-3))/((x-3)(x-3)(x+3))
= ....
take over
3/(x^2-9)-x/(x^2-6x+9)+1/(x+3)
2 answers
Hmm. I get
(3(x-3) - x(x+3) + 1(x-3)(x-3)) / ((x-3)(x-3)(x+3))
(3(x-3) - x(x+3) + 1(x-3)(x-3)) / ((x-3)(x-3)(x+3))