3 Vocabulary - 5 Problems U6 L9

Question

Unit 6 3Vs/5Ps Links - Click here
Unit 6 L6 - L9 Live Lesson Recording - you will have to go to the push pin message board to get the password

What do you need to know how to do in this selection?

3 Vocabulary Terms - Define/Illustrate

Words that tell you have a right triangle:
Hypotenuse, opposite, adjacent

Why draw a picture in Geometry?
Drawing a picture is a good way of describing solutions to a problem.

Longitude and Latitude for navigation and PT?
Longitude is an east-west position measured from the prime meridian
Latitude is north and south from earth’s equator.

5 Problems - SHOW ALL WORK!

Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet long and the bottom of the house is 6 feet across. What is the height of his dog house, in feet, at its tallest point?
Draw a picture:

Solve: 5^2+h^2=6^2
25+h^2=36
h^2=36-25
h=sqrt 11
h=3.32
The tallest point of the doghouse is 3.32 ft

A baseball diamond is a square with sides of 90 feet. What is the shortest distance between first base and third base?

Draw a picture:

Solve:
c^2=90^2+90^2
c^2=8100+8100
c^2=16200
c=sqrt 16200
c=127.3

The shortest distance between first and third base is 127.3 ft.
Best Buy is selling 55 inch HD TV’s. This measurement is the diagonal distance across the screen. If the screen measures 48 inches in width, what is the actual height of the screen?
Draw a picture:

Solve: (h^2+48^2)=55^2
h^2_2304=3025
h^2=721
h=sqrt 721
h=26.58 inches
The actual height is 26.85 inches.


Two joggers run 8 miles north and then 5 miles west. What is the shortest distance they must travel to return to their starting point?
Draw a picture:

Solve:
8^2+5^2=c^2
64+25=c^2
89=c^2
Sqrt 89=c
c=9.43
The shortest distance they must travel to return to the starting point is about 9.43 miles.
You're locked out of your house and the only open window is on the second floor, 25 feet above the ground. You need to borrow a ladder from one of your neighbors. There's a bush along the edge of the house, so you'll have to place the base of the ladder 10 feet from the house. What length of ladder do you need to reach the window?

Draw a picture:

Solve:x^2=10^2+25^2
x^2=100+625
x^2=725
x=sqrt 725
x=26.65

The ladder will need to be 26.65ft long for it to reach the window.


What do I need help with?

Answer 1

It appears that you may need help with understanding how to solve problems involving right triangles and calculating distances using the Pythagorean theorem. Additionally, you may need help with visualizing geometric problems and showing all the work in a clear and organized manner. Practicing drawing pictures and organizing your work step by step may help improve your problem-solving skills in geometry. If you need further assistance, consider reaching out to your teacher or a tutor for additional guidance.