mols H2 = grams/molar mass = 8.08/2 = 4.04. (I rounded for the molar mass H2; you may want to do it more accurately.)
Convert mols H2 to mols O2 using the coefficients in the balanced equation.
4.04 mols H2 x (1 mol O2/2 mols H2) = 4.04 x 1/2 = 2.02 mols O2 needed to react with 8.08 g H2.
Then g O2 = mols O2 x molar mass O2 = 2.02 mol x 32 g/mol = ?
3. Use the ratio of stoichiometric coefficients in the reaction above to determine how many moles of O2 will react with the H2 available.
Then, use molar mass to convert the moles of O2 into grams.
For the reaction 2H2 + 1O2 =2H2O, there are 8.08 grams of H2 available.
the ratio would be 2 h2 to 1 o2 but i don't know how to go from there how would u set it up?
there would be 32 g per mole for the mass of oxygen do u multiply 2 times 32?
2 answers
2. Use the ratio of stoichiometric coefficients in the reaction above to determine how many moles of H2O can be produced from the H2 available.
Then, use molar mass to convert the moles of H2O into grams.
For the reaction 2H2 + 1O2 à 2H2O, there are 8.08 grams of H2 available.
I got the answer 324.36 grams would that be correct
Then, use molar mass to convert the moles of H2O into grams.
For the reaction 2H2 + 1O2 à 2H2O, there are 8.08 grams of H2 available.
I got the answer 324.36 grams would that be correct