3. The mean volume of draught beer served in pint glasses in a particular pub is known to be 0.564 litres. A consumer organization takes a random sample of 64 pints of draught beer and finds that the standard deviation of this sample is 0.025 litres. What is the probability that the mean volume of the sample will be more than a pint (0.564 litres)?

asked by najma

13 years ago

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Z = (score-mean)/SEm

SEm = SD/√n

Use the same table as on your previous post.

answered by PsyDAG

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3. The mean volume of draught beer served in pint glasses in a particular pub is known to be 0.564 litres. A consumer organization takes a random sample of 64 pints of draught beer and finds that the standard deviation of this sample is 0.025 litres. What is the probability that the mean volume of the sample will be more than a pint (0.564 litres)?

1 answer

Z = (score-mean)/SEm

SEm = SD/√n

Use the same table as on your previous post.

Ask a New Question or answer this question.

PsyDAG · Answer

Z = (score-mean)/SEm SEm = SD/√n Use the same table as on your previous post.