when t = 0
S(0) = 68 - 20log(1) = 68
when t= 4
S(4) = 68 - 20log(5) = 54.02... or 54
etc.
for score to be 50
50 = 68 - 20log(t+1)
log(t+1) = 18/20 = .9
t+1 = 10^.9
t = 10^.9 - 1 months
= 6.943 or appr. 7 months
3. Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by
S(t) = 68 − 20 log (t + 1), t ¡Ý 0.
What was the average score when they initially took the test, t = 0?
Round your answer to a whole percent, if necessary.a)Answer:
Show your work in this space:
What was the average score after 4 months? after 24 months?
Round your answers to two decimal places.b)Answer:Show your work in this space:
After what time t was the average score 50%?Round your answe
1 answer
2 answers