Let's define the variables:
Let L be the length of the rectangle.
Let W be the width of the rectangle.
From the given information, we know that the length of the rectangle is equal to triple the width, so we can write the equation:
L = 3W
We also know that the perimeter of a rectangle is given by the equation:
Perimeter = 2L + 2W
Substituting the value of L from the first equation into the second equation, we can write:
86 = 2(3W) + 2W
Now we can solve the equation for W:
86 = 6W + 2W
86 = 8W
W = 86/8
W = 10.75
Substituting the value of W back into the equation L = 3W, we can find the length:
L = 3(10.75)
L = 32.25
Therefore, the dimensions of the rectangle are 32.25 cm for the length and 10.75 cm for the width.
3. Solving systems of equations word problems worksheet For all problems, define variables, write the system of equations and solve for all variables.
-The length of a rectangle is equal to triple the width. Which system of equations can be used to find the dimensions of the rectangle if the perimeter is 86 centimeters?
1 answer