1/r1 + 1/r2 + 1/r3 = 1/r = 1/1000
r2 = 3r1
r2 = 2r3
Substitute and solve for r2 and evaluate for r1 and r3.
Show your work if you get stuck.
3 resistor in parallel have an equivalent resistance of 1000 ohms. If R2 is twice the value of R3 and trice the value of R1, what is the value of R1,R2 and R3? Please show me the sol'n. n_n
2 answers
R3 = R Ohms.
R2 = 2R Ohms.
R1 = 2R/3 Ohms.
1/R1 + 1/R2 + 1/R3 = 1/1000
1/(2R/3) + 1/2R + 1/R = 1/1000
3/2R + 1/2R + 1/R = 1/1000
3/2R + 1/2R + 2/2R = 1/1000.
6/2R = 1/1000.
3/R = 1/1000.
R/3 = 1000.
R = 3000 Ohms.
R1 = 2R/3 = 6000/3 = 2000 Ohms.
R2 = 2R = 2*3000 = 6000 Ohms.
R3 = R = 3000 Ohms.
R2 = 2R Ohms.
R1 = 2R/3 Ohms.
1/R1 + 1/R2 + 1/R3 = 1/1000
1/(2R/3) + 1/2R + 1/R = 1/1000
3/2R + 1/2R + 1/R = 1/1000
3/2R + 1/2R + 2/2R = 1/1000.
6/2R = 1/1000.
3/R = 1/1000.
R/3 = 1000.
R = 3000 Ohms.
R1 = 2R/3 = 6000/3 = 2000 Ohms.
R2 = 2R = 2*3000 = 6000 Ohms.
R3 = R = 3000 Ohms.