3 radical 3=-3 cot theta

Question

on interval 0<theta<2pi

Answer 1

3√3 = -3cotθ

cotθ = -√3

cot is negative in QII and QIV

arccot(√3) = π/6

so, θ = π-π/6 or 2π-π/6
= 5π/6 or 11π/6