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Question

Question
Use the information in the table to answer the question.

Bond Bond Energy ( kJ/mol )
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I2→2HI

How much total bond energy in kJ/mol is in the products of the reaction?

(1 point)
Responses

297
297

594
594

448
448

453

Answer 1

To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we first need to know the bond energy of the products.

In the reaction, we produce 2 moles of \( HI \). The bond energy of \( H-I \) is given as 297 kJ/mol. Therefore, for 2 moles of \( HI \):

\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of } H-I = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]

So, the total bond energy in the products of the reaction is:

594 kJ/mol