To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we first need to know the bond energy of the products.
In the reaction, we produce 2 moles of \( HI \). The bond energy of \( H-I \) is given as 297 kJ/mol. Therefore, for 2 moles of \( HI \):
\[ \text{Total bond energy in products} = 2 \times \text{Bond energy of } H-I = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]
So, the total bond energy in the products of the reaction is:
594 kJ/mol