To solve the equation \( 3(n + 3) = 4n + 30 \), we can follow these steps:
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Distribute the 3 on the left side: \[ 3n + 9 = 4n + 30 \]
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Next, we'll move all terms involving \( n \) to one side and constant terms to the other. Subtract \( 3n \) from both sides: \[ 9 = 4n - 3n + 30 \] This simplifies to: \[ 9 = n + 30 \]
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Now, isolate \( n \) by subtracting 30 from both sides: \[ 9 - 30 = n \] This simplifies to: \[ n = -21 \]
So, the solution is: \[ \boxed{-21} \]