(3^m)(5^(m+1))=12^(2m-1)

Question

not sure how to solve this but I think you use natural logs? I'm just stuck because the first two are multiplying and not adding and we didn't go over this

Answer 1

yes, take the log of both sides

log(3^m)(5^(m+1)) = log(12^(2m-1)

mlog3 + (m+1)log5 = (2m-1)log12

expand and you will get terms of m and constants, remember something like log12 is a constant
factor out m from the "m-terms" and solve for m

It is messy and long, be careful.

Answer 2

I just solved for each log individually on my calculator and used decimals to find the answer, and it ended up being right

thanks!