1 mol Fe for every 2 mol HBr. 55.85grams fe per 161.816 g hbr.
3.2 grams fe x(161.816g hbr/55.85g fe)=9.27g fe
3. Hydrobromic acid dissolves solid iron according to the following reaction:
Fe(s) + 2HBr(aq) ---> FeBr2(aq) + H2(g)
What mass of HBr (in g) would you need to dissolve a 3.2 gram pure iron bar on a padlock?
What mass of H2 would be produced by the complete reaction of the iron bar?
1 answer