If you combine terms you see that it's just
y = (x+3)^2/3x
y' = 1/3 - 3/x^2
y'' = -6/x^3
Continuous except where denominator is zero
rising/falling where y' is positive/negative
concave up where y'' > 0
max/min where y' = 0
3. Discuss the graph of y=x/3+2+3/x. Determine the values of x for which the graph is
a. Continuous
b. Rising
c. Falling
d. Concave upward
e. Concave downward
f. Has a relative maximum
g. Has a relative minimum
2 answers
Oops
y'' = 6/x^3
y'' = 6/x^3
1 answer