3. Determine that the vectors u=[t, 4, 2t+1] and v=[t+2, 1-t, -1] are perpendicular, find the possible values of the contant, t.

Answer 1

Same as previous question,
http://www.jiskha.com/display.cgi?id=1337914331

Except that the dot-product equated to zero results in a quadratic equation.

So solve for possible values of t by solving the quadratic.

Answer 2

t(t+2) + 4(1-t) - (2t+1) = 0
t = 1,3

like that?

Answer 3

Correct!

Answer 4

thanks