Asked by Annabella Richards
3 consecutive numbers multiply to 4080. What are the numbers?
Answers
Answered by
drwls
Let the middle number be x.
(x-1)x(x+1) = x^3 - x = 4080
x = 16 works
I did not solve the cubic equation, but knew the answer had to be an integer slightly larger than the cube root of 4080.
The numbers are 15, 16 and 17.
(x-1)x(x+1) = x^3 - x = 4080
x = 16 works
I did not solve the cubic equation, but knew the answer had to be an integer slightly larger than the cube root of 4080.
The numbers are 15, 16 and 17.
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