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3 Cl2 + 6 KOH go to KClO3 + 5 KCl + 3 H2O how many moles of KClO3 form when 2 grams of KOH react completely

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Convert gms to moles (divide given mass in grams by formula weight) and use equation ratio... f.wt.(KOH) = 56 g/mole

2gms KOH = (2/56)mole KOH = 0.036mole KOH

fm equation 6molesKOH => 1moleKClO3

then ... (6/0.036) = (1/x) => x = (0.036/6)mole KClO3 = 0.006 mole KClO3
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