The distance traveled by the runner is given by the formula:
d(h) = s(h) × t(h)
Substitute the given functions for s(h) and t(h):
d(h) = 2vh × 3v4h
d(h) = 6v^2h × 3v^4h
d(h) = 18v^6h^2
So, the distance traveled by the runner is 18v^6h^2.
3. A runner's speed is given by the function s(h) = 2vh and the associated time is given by the function t(h) =3v4h. What distance did the runner
travel?
d(h)=12h
d(h)= 12
d(h)=3
d(h)=hv3
1 answer