v=4/3Πr^3
=4/3×pie×(6.38×10^6)^4
=1.08×10^21
therefore
D=m/v
=5.98×10^24kg/1.08×10^21m3
=5.49×10^3kg/m3
3. A model of Earth’s interior: Look up the radius and mass of the Earth.
Radius is 6,371 km
Mass is 5.974 x 10^24 kg
Calculate its average density.
p_e = (5.974 x 10^24 kg)/ (4/3)pi r^3 =
(5.974 x 10^24 kg)/ (4/3)pi (6371)^3 = 5.54 g/cm^3
Using this Imagine a planet of the same radius made completely and uniformly out of an incompressible fluid such that its mass density is equal to the average density of the Earth.
Now, use the equation of hydrostatic equilibrium to find the pressure as a function of distance from the center. What is the pressure at the center of the planet? Express your answer in Atmospheres.
1 answer
1 answer