3×a√1x= 27-x find x

Answer 1

You wrote √1, but since that is just 1, I suspect you meant √(1x). That's also weird, but let's go with it.

3a√x= 27-x
9a^2x = 729-54x+x^2
x^2-(9a^2+54)x+729 = 0
Now use the quadratic formula to get

x = 9a/2 (a+6±√(a^2+12))

That's kind of messy, so if there was a typo somewhere, fix it and redo the steps.

Answer 2

Looks messy to my also. Sulaiman, don't forget to use parenthesis in these complex equations.