3*+4y=5/2*-5=12 substation

1 answer

It looks like the equation you've given may need some clarification. It seems to combine various operations in an unclear way. Let's break it down to understand it better.

  1. 3+4y*: This part is ambiguous. If you meant \(3 + 4y\), that would make sense as an algebraic expression.
  2. 5/2-5*: This could be interpreted in several ways. It likely means \(\frac{5}{2} \times -5\). This simplifies to \(-\frac{25}{2}\).
  3. =12: This is the end of an equation.

If we summarize this, you might want to create an equation that looks something like:

\[ 3 + 4y = -\frac{25}{2} + 12 \]

Let's calculate the right side:

\[ 12 = \frac{24}{2} \] So combining, we have:

\[ -\frac{25}{2} + \frac{24}{2} = -\frac{1}{2} \]

Thus, the equation now reads:

\[ 3 + 4y = -\frac{1}{2} \]

Now, we can solve for \(y\):

  1. Subtract 3 from both sides:

\[ 4y = -\frac{1}{2} - 3 \]

Convert 3 to have a common denominator:

\[ 3 = \frac{6}{2} \]

So we continue:

\[ 4y = -\frac{1}{2} - \frac{6}{2} = -\frac{7}{2} \]

  1. Divide both sides by 4:

\[ y = -\frac{7}{2} \div 4 = -\frac{7}{2} \times \frac{1}{4} = -\frac{7}{8} \]

Thus, the solution for \(y\) is:

\[ y = -\frac{7}{8} \]

If your equation intended something different, please clarify!