To find the fraction of the class that studies mathematics but not English, we need to subtract the fraction that studies both subjects from the fraction that studies only mathematics.
Given that 3/4 of the class studies English, we can find the fraction that studies both subjects by multiplying 3/4 by 3/8:
(3/4) * (3/8) = 9/32
So, 9/32 of the class studies both subjects.
To find the fraction that studies only mathematics, we need to subtract 9/32 from the fraction that studies only mathematics and English. We know that the total fraction that studies mathematics is 3/8. So, to find the fraction that studies only mathematics, we subtract 9/32 from 3/8:
(3/8) - (9/32) = (6/32) - (9/32) = -3/32
Since the fraction cannot be negative, we know that at least one error has been made in the problem or the calculations. Therefore, the given answer choices do not accurately represent the situation.
3/4 of a class of 32 students
study English and 3/8 study
mathematics. Every student
studies at least one of these
subjects. What fraction of the
class study mathematics but not
English?
A. 3/4
B. 5/8
C. 3/8
D. 8/9
1 answer