To solve \( \frac{3}{4} - 1 \frac{3}{4} \):
First, convert \( 1 \frac{3}{4} \) into an improper fraction: \[ 1 \frac{3}{4} = \frac{4 \times 1 + 3}{4} = \frac{4 + 3}{4} = \frac{7}{4} \]
Now subtract \( \frac{7}{4} \) from \( \frac{3}{4} \): \[ \frac{3}{4} - \frac{7}{4} = \frac{3 - 7}{4} = \frac{-4}{4} = -1 \]
Thus, the final answer is: \[ 3 \div 4 - 1 \frac{3}{4} = -1 \]