3.2g of a mixture of kn03 and nan03 was heated to constant weight which was found to be 2.64g. What is the % kn03 in mixture
the answer 44.22%
2 answers
If I get time I will look at this, but really you need a chemistry teacher.
2KNO3 ==> 2KNO2 + O2 and
2NaNO3 ==> 2NaNO2 + O2
Let X = mass KNO3
and Y = mass NaNO3
---------------------
eqn 1 is X + Y = 3.2
eqn 2 is
X(molar mass KNO2/KNO3) + Y(molar mass NaNO2/NaNO3) = 2.64
Solve the two equations simultaneously to find X, then
%X = (mass X/3.2)*100 = ?
2NaNO3 ==> 2NaNO2 + O2
Let X = mass KNO3
and Y = mass NaNO3
---------------------
eqn 1 is X + Y = 3.2
eqn 2 is
X(molar mass KNO2/KNO3) + Y(molar mass NaNO2/NaNO3) = 2.64
Solve the two equations simultaneously to find X, then
%X = (mass X/3.2)*100 = ?
1 answer