3.22g of hydrated sodium sulphate na2so4xh2o were heated to a constant mass of 1.42g determine the value of x in the formula(Na=23.0,s=32.0,0=16,h=1)

Answer 1

First, we need to find the mass of anhydrous sodium sulfate (Na2SO4):

3.22g - 1.42g = 1.80g

Next, we need to calculate the moles of anhydrous Na2SO4:

1.80g / 142g/mol = 0.0127 mol

Since Na2SO4 reacts in a 1:1 ratio with water, the number of moles of water in the original hydrated compound is also 0.0127 mol.

Now, we can use the molar mass of the hydrated compound (142g/mol) to calculate the mass of water:

142g/mol - 112g/mol = 30g/mol

30g/mol x 0.0127 mol = 0.381g

Finally, we can use the mass of water and the mass of the hydrated compound to determine the value of x:

xH2O = (mass of water / mass of hydrated compound) x formula weight of water

xH2O = (0.381g / 3.22g) x 18g/mol

xH2O = 0.134

Therefore, the value of x in the formula Na2SO4·xH2O is approximately 0.134.