A slight twist on limiting reagent (LR).
CaCl2 _+ Na2SO4 ==> CaSO4 + 2NaCl
mols CaCl2 = grams/molar mass = ?
mols Na2SO4 = grams/molar mass = ?
Using the coefficients in the balanced equationk convert mols Cacl2 to mols CaSO4.
Do the same and convert mols Na2SO4 to mols CaSO4.
It is likely that these two values will not agree; the correct value in LR problems is ALWAYS the smaller value the reagent responsible for that value is the LR. The other is the excess reagent (ER).
To find how much of the ER is used, convert mols LR to mols ER. Subtract the initial amount of the ER - amount ER used = amount ER remaining unreacted.
3.2 grams of calcium chloride reacts with 3.55 grams of sodium sulfate producing calcium sulfate + sodium chloride. Which is the reactant in excess and the excess mass?
Cacl2 + Na2SO4 = CaSO4 + NaCl
1 answer
1 answer