I assume you that you need to solve for x?
3/2(4x-6)-x(3-x)=1/3x(3x-6)
multiply through by 2 and by 3 to remove the fractions
9(4x-6)-6x(3-x)=2x(3x-6)
remove the brackets
36x-54-18x+6x^2=6x^2-12x
36x-54-18x=-12x
group like terms
18x-54=-12x
30x=54
hence find x
Check my algebra!
3/2(4x-6)-x(3-x)=1/3x(3x-6)
1 answer