what a mish-mash of inappropriate symbols and unbalanced parentheses!!
I'll assume you meant
3^(2x) - 4(3^(x+1) + 27) = 0
3^(2x) - 4*3^(x+1) - 108 = 0
3^(2x) - 12*3^x - 108 = 0
(3^x - 18)(3^x + 6) = 0
3^x = 18 or -6
the only real solution is 3^x = 18, or
x = log318 = log18/log3
3^(2×)_4(3^(x+1)+27=0
1 answer