3×10^18 photons of a certain light radiation are found to produce 1.5 j of energy. calculate the wavelength of light radiation

Answer 1

E=nhc/lamda
>1.5= 3*10^18 * 6.626*10^-34 * 3*10^8/ lamda(wavelength)

Therefore wavelength =3.973*10^-7

Answer 2

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Answer 3

E= nhc/ lambda
1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
Lambda= 9×10^26 × 6.626×10^-34
÷ 1.5
Lambda = 39.75×10^-8 = 3975 Å

Answer 4

Question

Answer 5

Calculate the wavelength & the period of a blue light wit a energy 5 X 10^-19 J

Answer 6

E= nhc/ lambda
1.5= 3×10^18 × 6.626×10^-34 × 3×10^8 / lambda
Lambda= 9×10^26 × 6.626×10^-34
÷ 1.5
Lambda = 39.75×10^-8 = 3975 Å

Answer 7

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