Question
(-3, -1)
(2, -1)
(2, 3)
When the three medians of the triangle are drawn, they meet at single point. What is the point of the centroid? Leave all the results in fractions
centroid ( _, _)
(2, -1)
(2, 3)
When the three medians of the triangle are drawn, they meet at single point. What is the point of the centroid? Leave all the results in fractions
centroid ( _, _)
Answers
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Answered by
GPT-4o mini
To find the centroid of a triangle defined by the vertices \((-3, -1)\), \((2, -1)\), and \((2, 3)\), we use the formula for the centroid \((G_x, G_y)\):
\[
G_x = \frac{x_1 + x_2 + x_3}{3}, \quad G_y = \frac{y_1 + y_2 + y_3}{3}
\]
Where:
- \((x_1, y_1) = (-3, -1)\)
- \((x_2, y_2) = (2, -1)\)
- \((x_3, y_3) = (2, 3)\)
Now we can calculate \(G_x\) and \(G_y\):
First, we calculate \(G_x\):
\[
G_x = \frac{-3 + 2 + 2}{3} = \frac{1}{3}
\]
Next, we calculate \(G_y\):
\[
G_y = \frac{-1 + (-1) + 3}{3} = \frac{1}{3}
\]
Thus, the coordinates of the centroid are:
\[
\text{centroid} \left( \frac{1}{3}, \frac{1}{3} \right)
\]
Final answer:
\(\text{centroid} \left( \frac{1}{3}, \frac{1}{3} \right)\)
\[
G_x = \frac{x_1 + x_2 + x_3}{3}, \quad G_y = \frac{y_1 + y_2 + y_3}{3}
\]
Where:
- \((x_1, y_1) = (-3, -1)\)
- \((x_2, y_2) = (2, -1)\)
- \((x_3, y_3) = (2, 3)\)
Now we can calculate \(G_x\) and \(G_y\):
First, we calculate \(G_x\):
\[
G_x = \frac{-3 + 2 + 2}{3} = \frac{1}{3}
\]
Next, we calculate \(G_y\):
\[
G_y = \frac{-1 + (-1) + 3}{3} = \frac{1}{3}
\]
Thus, the coordinates of the centroid are:
\[
\text{centroid} \left( \frac{1}{3}, \frac{1}{3} \right)
\]
Final answer:
\(\text{centroid} \left( \frac{1}{3}, \frac{1}{3} \right)\)
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