(2y-1)dy/dx=(3x^2+1) given that x=1 when y=2

Question

plz show step thanks

Answer 1

huh? simple separation of variables.

(2y-1) dy = (3x^2+1) dx
y^2-y = x^3+x + C
Using your point (1,2), find C:
4-2 = 1+1+C
C = 0

y^2-y = x^3+x
y = (1±√(4x^3+4x+1))/2