Expanding the product of (2y-1)(4y-3), we use the FOIL method:
(2y-1)(4y-3) = 2y(4y) - 2y(3) - 1(4y) + 1(3)
= 8y^2 - 6y - 4y + 3
= 8y^2 - 10y + 3
Therefore, (2y-1)(4y-3) = 8y^2 - 10y + 3.
(2y-1)(4y-3)
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1 answer