2xy + 3 + 2y + 3x factorize

1 answer

To factor the expression \(2xy + 3 + 2y + 3x\), we can first rearrange the terms:

\[ 2xy + 3x + 2y + 3 \]

Next, we can group the terms:

\[ (2xy + 3x) + (2y + 3) \]

Now, we can factor out common factors from each group:

From the first group, \(2xy + 3x\), we can factor out \(x\):

\[ x(2y + 3) \]

From the second group, \(2y + 3\), we leave it as is since there are no common factors to factor out.

Now, putting it together:

\[ x(2y + 3) + 1(2y + 3) \]

Notice that \(2y + 3\) is common in both terms, so we can factor it out:

\[ (2y + 3)(x + 1) \]

Thus, the factorized form of the expression \(2xy + 3 + 2y + 3x\) is:

\[ (2y + 3)(x + 1) \]