-2x=7y-13 ; x=3

Answer to this problem above is y=-2/7x+13/7 : y=1

1 answer

To solve the equations you provided, we start with the first equation:

\[ -2x = 7y - 13 \]

Given that \( x = 3 \), we can substitute \( x \) into the equation:

\[ -2(3) = 7y - 13 \]

This simplifies to:

\[ -6 = 7y - 13 \]

Now, add 13 to both sides to isolate the term with \( y \):

\[ -6 + 13 = 7y \]

\[ 7 = 7y \]

Now, divide both sides by 7 to solve for \( y \):

\[ y = 1 \]

Now, regarding the second part of your statement, it appears you were trying to express the equation in slope-intercept form \( y = mx + b \). Let's derive that from the original equation:

Starting from:

\[ -2x = 7y - 13 \]

We arrange it to solve for \( y \):

\[ 7y = -2x + 13 \]

Now, divide every term by 7:

\[ y = -\frac{2}{7}x + \frac{13}{7} \]

So you are correct; the equation can indeed be expressed as:

\[ y = -\frac{2}{7}x + \frac{13}{7} \]

And we also found \( y = 1 \) when \( x = 3 \).