One way to solve the system of equations is by elimination. First, we can multiply the first equation by 5 and the second equation by 2 to make the coefficients of x the same:
10x - 15y = 80
10x - 6y = 26
Then, we can subtract the second equation from the first to eliminate x:
-9y = 54
Solving for y, we get:
y = -6
Substituting y=-6 into either of the original equations, we can solve for x:
2x - 3(-6) = 16
2x + 18 = 16
2x = -2
x = -1
Therefore, the solution is (-1, -6) which corresponds to answer choice A.
2x - 3y = 16
5x - 3y = 13
Solve the system of equations.
A (-1, -6)
B (5,4)
C (1,-14/3)
D (-6, -1)
E (5, -2)
1 answer
2 answers