cross multiply:
(2x+3)*(5x-9) = (3x-6)*(5x+3)
double distribution:
10x^2 - 3x -27 = 15x^2 - 21x - 18
combine like terms:
0 = 5x^2 -18x + 9
Then factor it to find two values of x
(2x+3)/(3x-6) = (5x+3)/(5x - 9)
2 answers
(2x+3)*(5x-9)=(3x-6)*(5x+3)
(2x+3)*(5x-9)=(5x+3)*(3x-6)
10x^2+15x-18x-27=15x^2+9x-30x-18
10x^2-3x-27=15x^2-21x-18
0=15x^2-10x^2+3x-21x+3x-18+27
5x^2-18x+9=0
If you want to know that solutions in google type:
quadratic equation online
When you see list of results click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
When page be open in rectacangle type:
5x^2-18x+9=0
and click option solve it
You will see solution step-by-step
(2x+3)*(5x-9)=(5x+3)*(3x-6)
10x^2+15x-18x-27=15x^2+9x-30x-18
10x^2-3x-27=15x^2-21x-18
0=15x^2-10x^2+3x-21x+3x-18+27
5x^2-18x+9=0
If you want to know that solutions in google type:
quadratic equation online
When you see list of results click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
When page be open in rectacangle type:
5x^2-18x+9=0
and click option solve it
You will see solution step-by-step