2x^2-12x+32=x^2
x^2 - 12x + 32 = 0
(x-8)(x-4) = 0
x = 8 or x = 4
2x^2-12x+32=x^2 how would I solve this by factoring?
2 answers
2x^2 - 12x + 32 = x^2
Move x^2 to the left side and change sign then put zero after equal sign..
2x^2 - x^2 - 12x + 32 = 0
x^2 - 12x + 32 = 0
(x - 4)(x - 8) = 0
x - 4 = 0 x - 8 = 0
x - 4 + 4 = 0 + 4 x - 8 + 8 = 0 + 8
x = 4 x = 8
x = 4,8
Move x^2 to the left side and change sign then put zero after equal sign..
2x^2 - x^2 - 12x + 32 = 0
x^2 - 12x + 32 = 0
(x - 4)(x - 8) = 0
x - 4 = 0 x - 8 = 0
x - 4 + 4 = 0 + 4 x - 8 + 8 = 0 + 8
x = 4 x = 8
x = 4,8
1 answer