(2x+1)/(8x+1)

Question

f is increasing for x:
f is decreasing for x:
find local max/min:

Answer 1

y = (2x+1)/(8x+1)
y' = -6/(8x+1)^2

Since (8x+1)^2 is always positive, y' is never zero, so the are no mins or maxes.

y is always decreasing. Check its graph to see how this can be.