2SO2(g) + O2(g) ---> 2SO3

Question

It says that 12.0 L of sodium trioxide are produced at 100 degrees celcius. What volume of oxygen is produced?

How would I go about doing this. I was going to use PV=nRT but I dunno the pressure so I can't find the moles. What do I do?

Answer 1

a. SO3 is sulfur trioxide, not sodium trioxide.
b. There is no oxygen produced. Oxygen is on the reactant side.
c. In gaseous reactions, it isn't necessary to convert to mols. You may use volume directly; i.e., 12.0 L SO3 produced means 6.0 L oxygen were used (if the reaction goes to completion).
d. note the correct spelling of Celsius.

Answer 2

How do you know it was 6 L of oxygen? I don't understand :S

Answer 3

The equation tells us (if the reaction goes to completion) that 1 mol O2 produces 2 mols SO3. Those are the coefficients in the balanced equation. Therefore,
12 L SO3 x (1 mol O2/2 mol SO3) = 6 L O2.