2NH3(g) =N2(g)+3H2(g), calculate the total energy required to break the bonds

Answer 1

In the given reaction, 4 N-H bonds and 6 H-H bonds are broken.

The average bond energies for N-H and H-H bonds are 391 kJ/mol and 436 kJ/mol, respectively.

Total energy required to break the bonds = (4 x 391 kJ/mol) + (6 x 436 kJ/mol)
= 1564 kJ + 2616 kJ
= 4180 kJ

Therefore, the total energy required to break the bonds in the reaction 2NH3(g) = N2(g) + 3H2(g) is 4180 kJ.