To calculate the number of moles of NaN3 needed to fill a 65 L airbag, we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (assumed atmospheric pressure, which is 1 atm)
V = Volume
n = Number of moles
R = Ideal Gas Constant (0.0821 L.atm/mol.K)
T = Temperature (30 °C, which needs to be converted to Kelvin)
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 30 °C + 273.15
T(K) = 303.15 K
Now, we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
Plugging in the values:
P = 1 atm
V = 65 L
R = 0.0821 L.atm/mol.K
T = 303.15 K
n = (1 atm * 65 L) / (0.0821 L.atm/mol.K * 303.15 K)
n = 2.14329303551 moles
Therefore, approximately 2.14 moles of NaN3 are needed to fill a 65 L airbag.
2NaN3(s) -› 2Na(s) + 3N.(g)
This reaction produces nitrogen to inflate airbags in cars. Sodium Azide (NaNs) produces Nitrogen (N2) very quickly in a crash.How many moles of NaN, are needed to fill a 65 L airbag?
Assume the gas is produced at a temperature of 30 °C
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1 answer