You have written the complete ionic equation. To turn this into the net ionic equation just do this. Cancel the ions that appear on both sides. What's left is the net ionic equation.
2Na^+ are on both sides. Cancel.
2NO3^- are on both sides. Cancel.
Zn^2+(aq) + 2OH^-(aq) ==> Zn(OH)2(s) is what's left.
2Na+(aq) + 2OH−(aq) + Zn2+(aq) + 2NO3−(aq) → Zn(OH)2(s) + 2Na+(aq) + 2NO3−(aq)
Write the net ionic equation for this precipitation reaction.
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