2M +6HCl–>2MCl+3H2 Delta H= -638.0 Kj

HClg—>HCl aq= Delta H -74.8 Kj
H2+Cl2–>2HCl Delta H -1845.0 Kj
MCl3s–> MCl3 aq Delta H -249.0 Kj

Use the information above to determine the enthalpy of the following reaction.

2M +3Cl2–>2MCl3 Delta H =???

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