2Li + S -> Li2S

Question

Oxidized element?

Reduced element?

Oxidizing agent?

Reduction agent?

Answer 1

In the reaction 2Li + S -> Li2S:

- The oxidized element is S (sulfur), as it gains electrons (goes from an oxidation state of 0 to -2 in Li2S).
- The reduced element is Li (lithium), as it loses electrons (goes from an oxidation state of 0 to +1 in Li2S).
- The oxidizing agent is Li, as it is the species that causes oxidation (loses electrons).
- The reduction agent is S, as it is the species that causes reduction (gains electrons).