The correct answer is:
Li loses electrons and is oxidized. F2 gains electrons and is reduced.
2Li(s) + F2(g) -> 2LiF (s)
• Li loses electrons and is oxidized. F2 gains electrons and is reduced.
Li gains electrons and is oxidized. F2 loses electrons and is reduced.
• F2 loses electrons and is oxidized. Li gains electrons and is reduced.
• F2 gains electrons and is oxidized. Li loses electrons and is reduced.
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