To determine how many grams of mercury(II) oxide (HgO) can be produced from a specific amount of mercury (Hg) and oxygen (O₂) using the equation:
\[ 2\text{Hg} + \text{O}_2 \rightarrow 2\text{HgO} \]
we first need to understand the molar masses of the substances involved.
-
Molar Masses:
- Molar mass of Hg (mercury): approximately 200.59 g/mol
- Molar mass of O₂ (oxygen): approximately 32.00 g/mol
- Molar mass of HgO (mercury(II) oxide): approximately 216.59 g/mol (200.59 g/mol for Hg + 16.00 g/mol for O)
-
Stoichiometry: According to the balanced chemical equation, 2 moles of Hg react with 1 mole of O₂ to produce 2 moles of HgO.
-
Grams of HgO Produced: If you are given a specific quantity of mercury or oxygen, you can convert that quantity to moles using the molar mass, and then use the stoichiometry of the reaction to calculate the grams of HgO produced.
Example Calculation:
Assuming we have 200 grams of mercury:
-
Calculate the moles of mercury: \[ \text{Moles of Hg} = \frac{200 \text{ g}}{200.59 \text{ g/mol}} \approx 0.997 \text{ moles of Hg} \]
-
According to the reaction, \(2 \text{ moles of Hg} \rightarrow 2 \text{ moles of HgO}\). Thus, the moles of HgO produced will be equal to the moles of Hg used: \[ \text{Moles of HgO} = 0.997 \text{ moles} \]
-
Now, calculate the grams of HgO produced: \[ \text{Grams of HgO} = \text{Moles of HgO} \times \text{Molar mass of HgO} \] \[ \text{Grams of HgO} = 0.997 \text{ moles} \times 216.59 \text{ g/mol} \approx 216.07 \text{ g} \]
Therefore, from 200 grams of mercury, about 216.07 grams of mercury(II) oxide (HgO) can be produced.
If you have a different amount of mercury or O₂, just adjust the calculations accordingly!
1 answer