2HCl(ag) + Zn(s) → ZnCl2(aq) + H2(g)

Question

The molar mass of hydrogen (H) is 1g/mol, the molar mass of chlorine (Cl) is 35g/mol, and the molar mass of zinc (Zn) is 65g/mol. When 130g of zinc react completely in hydrochloric acid (HCl), how much is the total mass of the products?

(1 point)
Responses

130g
130g

274g
274g

270g
270g

144g

Answer 1

The balanced chemical equation shows that 1 mole of zinc produces 1 mole of hydrogen gas and 1 mole of zinc chloride.

First, calculate the number of moles of zinc in 130g:

130g / 65g/mol = 2 moles of Zn

Since the molar ratio of Zn to H2 is 1:1, there will be 2 moles of H2 produced.

Now, calculate the mass of H2 produced:

2 moles x 1 g/mol = 2g

The total mass of the products will be the mass of ZnCl2 + the mass of H2:

65g (ZnCl2) + 2g (H2) = 67g

Therefore, the total mass of the products is 67g.

The closest answer choice is 70g.

Answer 2

which out of these choices is correct

Answer 3

Apologies for the mistake in my previous response. Let's recalculate the total mass of the products:

Given:
130g of Zn reacts.

Calculate the molar mass of ZnCl2:
Zn = 65g/mol
Cl = 35g/mol x 2 = 70g/mol
Total molar mass of ZnCl2 = 65g/mol + 70g/mol = 135g/mol

Now, calculate the moles of Zn:
130g / 65g/mol = 2 moles of Zn

The reaction produces an equal number of moles of ZnCl2, so there will be 2 moles of ZnCl2.

Calculate the total mass of ZnCl2 produced:
2 moles x 135g/mol = 270g

Since the only gas produced is H2, the total mass of the products will be 270g (ZnCl2) + mass of H2.

Calculate the mass of H2 produced:
2 moles of Zn reacting produces 1 mole of H2.
1 mole of H2 has a molar mass of 2g.

2 moles x 2g/mol = 4g

Add the mass of H2 to the total mass of ZnCl2:
270g (ZnCl2) + 4g (H2) = 274g

Therefore, the correct answer is:
274g