The maximum amount of useful work that can be done by a chemical reaction is given by dGo = dHo - TdSo. The units of dGo are kJ/mol so multiply the answr you get by 2.05moles.
Don't forget that dH usually is given in kJ/mol and dS usually is given in J/mol. The usual method is to convert the dSo value to kJ first.
Post your work if you get stuck.
2HBr(g) + Cl2(g)2HCl(g) + Br2(g)
ΔH° = -81.1 kJ and ΔS° = -1.2 J/K
The maximum amount of work that could be done when 2.05 moles of HBr(g) react at 274 K, 1 atm is...?
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