2h2s g 3o2 g 2so2 g 2h2o g H=-1036KG/MOL

Question

calculate enthalpy change in kj when 18.2 g of hydrogen sulfide are burned

Answer 1

I STRONGLY object to posts with no arrows, no plus signs, no caps (except in the wrong place), no periods, no parentheses, and no sentence structure. If you want us to help, you need to make your posts readable. I assume you intended to write
2H2S(g) + 3O2(g) ==> 2SO2(g) + 2H2O(g) delta H=-1036 kg/mol which should be kJ/mol.

1036 kJ/mol x (18.2g/molar mass H2S) = ?

Answer 2

llll