2H2O(l)=2H2(g) +O2(g)
if water is removed, the direction of equilibrium is unaffected since liquid water is not in the equil equation. What if large amount of water is removed, is the answer still the same
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As long as there is enough water(liquid) to provide the proper vapor pressure at the equilibrium temperature, then how much is removed is not in the equation. BUT there must be at least one drop there. If all of it is removed all bets are off.
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